- #1
DeanBH
- 82
- 0
damn annoying question. I'm basically new to this stuff, simple HS maths to you guys.
f(x) = X/2 -4/x^2 + 1
thats the line.
dy/dx is 1/2 + 8/x^3 that was first question.
2nd = the normal at point (2/1) on the curve above cuts the x and y axes at A and B respectively. Calculate the length of AB leaving answer in simplified surd form.
ok.
gradient of tangent at that point is 1/2 + 8/16 = 3/2
normal is -2/3.
ok, now from here I'm not sure where to go or what to do =( help =)
f(x) = X/2 -4/x^2 + 1
thats the line.
dy/dx is 1/2 + 8/x^3 that was first question.
2nd = the normal at point (2/1) on the curve above cuts the x and y axes at A and B respectively. Calculate the length of AB leaving answer in simplified surd form.
ok.
gradient of tangent at that point is 1/2 + 8/16 = 3/2
normal is -2/3.
ok, now from here I'm not sure where to go or what to do =( help =)