Taylor expansion-multivariable calculus(basic question)

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The Taylor expansion for a multivariable function F(x,y,z) around the point (a,b,c) is defined using partial derivatives and involves summing terms for all non-negative integer partitions of n. Each term in the expansion is represented as \frac{1}{n!}\frac{\partial f}{\partial x^i\partial y^j\partial z^k}(x- x_0)^i(y- y_0)^j(z- z_0)^k. The first few terms include the function value at the point and its first and second derivatives, demonstrating how to construct the expansion systematically. The discussion highlights the importance of understanding partitioning for calculating higher-order terms.

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What's the Taylor expansion of F(x,y,z) in the neighborhood of (a,b,c)?

Thank you
 
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Just extend the Taylor's expansion for functions of one variable.

For any n, let i, j, k be any non negative integers such that i+ j+ k= n.

One term in the Taylor's expansion, about [itex](x_0,y_0,z_0)[/itex], is
[tex]\frac{1}{n!}\frac{\partial f}{\partial x^i\partial y^j\partial z^k}[/itex][itex](x- x_0)^i(y- y_0)^j(z- z_0)^k[/itex].<br /> The entire Taylor's expansion is the sum for n= 0 to infinity, of the sum of all such terms for all "partitions" of n.<br /> <br /> Specifically, the "0" term has only i= j= k= 0 and is [itex]f(x_0,y_0,z_0)[/itex]. For n= 1, we have i=1, j= k= 0 so [itex]\partial f/\partial x(x_0,y_0,z_0)(x- x_0)+ \partial f/\partial y (x- y_0)[/itex][itex]+ \partial f/\partial z(x_0,y_0,z_0)(z- z_0)[/itex]. The second order terms are [itex](1/2)\partial^2f/\partial x^2 (x_0,y_0,z_0)(x- x_0)^2[/itex][itex]+ (1/2)\partial^2 f/\partial y^2(x_0,y_0,z_0)(y- y_0)^2[/itex][itex]+ (1/2)\partial^2 f/\partial z (x_0,y_0,z_0)(z-z_0)^2[/itex][itex]+ (1/2)\partial f^2/\partial x\partial y(x_0,y_0,z_0)(x-x_0)(y-y_0)+[/itex][itex](1/2)\partial f^2/\partial x_0\partial z_0(x_0,y_0,z_0)(x-x_0)(z-z_0)[/itex][itex]+ (1/2)\partial f^2/\partial y_0\partial z_0(x_0,y_0,z_0)(y-y_0)(z-z_0)[/itex].<br /> <br /> Do you get the idea? "3" can be partitioned as 3+ 0+ 0, 2+ 1+ 0, 2+ 0+ 1, 1+ 2+ 0, 1+ 0+ 2, 1+ 1+ 1, 0+ 3+ 0, 0+ 0+ 3, 0+ 1+ 2, and 0+ 2+ 1 so there are (if I counted correctly) 10 third degree terms[/tex]
 
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Thanks a lot HallsofIvy for this clear explanation!
I got the idea.
 

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