Taylor series with summation notation

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SUMMARY

The discussion focuses on deriving the Taylor series for the function f(x) = (1 - cos(x^2)) / x^3. Participants emphasize the importance of recognizing the Taylor series for cos(x) and manipulating the summation notation correctly. A specific example is provided, demonstrating how to express the function using a Taylor series expansion for sin(2x^3) and simplifying the expression by factoring out x. This approach clarifies the relationship between the Taylor series and the original function.

PREREQUISITES
  • Understanding of Taylor series expansions, specifically for trigonometric functions like cos(x).
  • Familiarity with summation notation and its manipulation.
  • Basic knowledge of limits and continuity in calculus.
  • Ability to perform algebraic simplifications involving series.
NEXT STEPS
  • Study the Taylor series for sin(x) and cos(x) in detail.
  • Learn how to manipulate summation notation in calculus.
  • Explore convergence criteria for Taylor series.
  • Practice deriving Taylor series for various functions beyond trigonometric examples.
USEFUL FOR

Students and educators in calculus, mathematicians focusing on series expansions, and anyone looking to deepen their understanding of Taylor series and their applications in mathematical analysis.

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Homework Statement



f(x) = \frac{1-cos(X^2)}{x^3}

which identity shoud i use?
and tips on this type of questions? once i can separate them, then i'll be good


thanks!
 
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Do you know a Taylor series for \cos x?
 
benorin said:
Do you know a Taylor series for \cos x?

yeah, but there's a x^3 on the bottom...
 
Sure, but the summation isn't over x so you can put the x in the sum or outside the sum.
 
Example:

\frac{1-\sin 2x^3}{x}=\frac{1-\sum_{k=0}^{\infty}\frac{\left( 2x^3\right)^{2k+1}}{(2k+1)!}}{x} = {\scriptstyle \frac{1}{x}}-{\scriptstyle \frac{1}{x}}\sum_{k=0}^{\infty}\frac{2^{2k-1}x^{6k+3}}{(2k+1)!}
= {\scriptstyle \frac{1}{x}}-\sum_{k=0}^{\infty}\frac{2^{2k-1}x^{6k+2}}{(2k+1)!}[/tex]​
 

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