Telescope focal length homework

Click For Summary

Homework Help Overview

The discussion revolves around a homework problem involving the focal length of a telescope and image formation. The original poster presents two questions: one about calculating the size of the telescope's image of the sun based on its focal length and another regarding the object distance for a converging mirror that produces a specific image size.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between object distance, image distance, and focal length using the lens formula. Some question the application of the formula and seek alternative methods for solving the problems presented.

Discussion Status

The discussion is ongoing, with participants providing insights into geometric relationships and the use of similar triangles to derive necessary equations. There is an indication of differing levels of understanding regarding the formulas involved, and some participants are encouraging exploration of simpler methods.

Contextual Notes

Participants note that certain formulas have not yet been covered in their coursework, which may impact their ability to approach the problems effectively. There is also a mention of the expectations from the instructor regarding the methods used for solutions.

ilovephysics9
Messages
6
Reaction score
0
Hey guys, I am really stuck on my homework review and really require help! Someone please help ! :(

Homework Statement


Question 1: A telescope has a focal length of 18m. If the suns diameter is about 1.39 x 10^9m and its distance from Earth is 1.49 x 10^11, how large is the telescopes image of the sun.
2. A converging mirror produces an image twice the size of the obbect. If the focal length is 20cm, find the object distance.

Homework Equations


1/f = 1/do + 1/di
m = -di/10 = hi/10
- FOR BOTH


The Attempt at a Solution


f = 18m
do = 1.49 x 10^11
ho = 1.39 x 10^9

1/f = 1/do + 1/d1
1/f - 1/do = 1/di
-0.56 = di
m = - (di)/do
= - (-0.56m / 1.49 x 10^11)
3.76 x 10 = m
m = hi / ho
3.76 x 10 ^10 = hi / 1.39x 10 ^...

THE FINAL ANSWER FOR THE QUESTION IS 17CM
 
Physics news on Phys.org
Q. 1
Image of the sun is framed at the focus of the objective. If you take two diametrically opposite rays from the sun to from the image at the focus, the optical center of the objective, ho and hi form two similar triangles. So
do/ho = di/hi. di is the focal length of the objective. Find hi.
Q.2 Show your attempt.
 
Hey there.. we haven't quite learned anything about the formula you told me about where di = f. the hi/di. Isn't there any other way i can possibly do it?
 
rl.bhat just used simple geometry to derive that equation, so I'm fairly certain that it's probably the solution your professor/teacher is looking for.
 

Similar threads

Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K