Temp equilibrium / latent heat

AI Thread Summary
To find the equilibrium temperature of a system with a heated iron block and water, the heat lost by the iron block must equal the heat gained by the water. The initial calculations suggest an equilibrium temperature of 242.95°C, but since water boils at 100°C, some water must vaporize. The heat lost by the iron block as it cools to 100°C equals the heat gained by the water to reach 100°C plus the latent heat required to convert some water to steam. To determine the amount of water that has vaporized, one must account for the latent heat of evaporation in the calculations. Understanding these principles is crucial for solving the problem correctly.
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Homework Statement


1 625g iron block is heared to 352 C is placed in an insulate container (of negligible heat capacity) containing 40g of water at 15 C. what is the equilibrium temp of this system? if your answer is 100 C, determine the amount of water that has vaporized.


Homework Equations


Q(block)=mc(T-Tblock) = .625(560)(T-352)
Q(water)=.040(4186)(T-15)

The Attempt at a Solution


set Q(block)=Q(water) i got T=242.95.. how was i suppose to get 100 C?

how do i solve how many grams of water have evaporated.

im so lost on this probelm, any help would be appreciated.
 
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When water reaches 100 C it turns to steam (it boils). To turn 1g of water at 100 C into 1g of steam at 100 C requires heat energy. That energy is called the "latent heat of evaporation".

You are doing OK so far. The equilibrium temp would have been 243 if the water didn't boil. but we know water boils at 100, therefore some water DID boil.

Heat out of block as it cools to 100 = heat into water to raise all the water to 100 + latent heat to convert some of the water to steam at 100.
 
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