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mppaki
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Before I begin, Please note that for some reason I don't really grasp physics equations which is odd since I had a A in chemistry but physics just confuses me and also, I am taking this class to prepare me for college. My pencil broke and I didn't think we would have homework of the stuff we learned so quick, so I decided not to ask anyone for a pencil and just listened through the rest of the lecture but now I regret it.
1. A 4.00 x 10²-g glass coffee cup is at room temperature, 20.0°C. It is then plunged into hot dishwater, 80.0°C. If the temperature of the cup reaches that of the dishwater, how much heat does the cup absorb? Assume the mass of the dishwater is large enough so its temperature doesn't change appreciably.
The only thing I can think of is Q=mC∆T, but I am pretty sure that is the wrong formula.
m = 4.00 x 10²g = 4000 / 1000 = 4kg.
Ti = 20.0°C
Tf = 80.0°C
C = 4180
Q = (4)(4180)(80-20)
Q = 1,003,200 j/kg * K
1. A 4.00 x 10²-g glass coffee cup is at room temperature, 20.0°C. It is then plunged into hot dishwater, 80.0°C. If the temperature of the cup reaches that of the dishwater, how much heat does the cup absorb? Assume the mass of the dishwater is large enough so its temperature doesn't change appreciably.
Homework Equations
The only thing I can think of is Q=mC∆T, but I am pretty sure that is the wrong formula.
The Attempt at a Solution
m = 4.00 x 10²g = 4000 / 1000 = 4kg.
Ti = 20.0°C
Tf = 80.0°C
C = 4180
Q = (4)(4180)(80-20)
Q = 1,003,200 j/kg * K
