Temperature generated by resistance wire?

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Discussion Overview

The discussion revolves around calculating the temperature generated by a semi-coiled resistance wire when powered by a 12VAC transformer. Participants explore the implications of wire resistance, power supply limitations, and the design of a heating element intended for a specific application, without reaching a definitive conclusion on the temperature output.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Experimental/applied

Main Points Raised

  • One participant presents a scenario involving 9.42 inches of resistance wire rated at 4.701 ohms/foot and questions the temperature generated when powered by a 12VAC source with a 600mA rating.
  • Another participant notes that the power supply may not provide sufficient current to drive the wire fully, suggesting that measuring the actual output would be more reliable than theoretical calculations.
  • A participant mentions that the shape of the wire (coiled vs. straight) affects the required current to achieve a certain temperature, referencing manufacturer claims about reduced current needs for coiled wire.
  • Concerns are raised about the safety and health implications of designing a cigarette lighter, with suggestions to consider heat transfer and heat loss in the design process.
  • One participant suggests that experimenting with different transformers and measuring equipment could yield better results, while another provides rough estimates of the current needed for specific temperatures based on wire type.
  • There is acknowledgment of the potential increase in wire resistance with temperature, although one participant argues it may be negligible for their application.

Areas of Agreement / Disagreement

Participants express differing views on the feasibility of achieving the desired temperature with the given power supply. There is no consensus on the exact temperature output or the best approach to design the heating element, indicating multiple competing views remain.

Contextual Notes

Participants highlight limitations such as the dependence on the power supply's performance, the potential for voltage sag, and the need to account for heat losses in the system. The discussion also reflects uncertainty regarding the impact of wire inductance and resistance changes at elevated temperatures.

Who May Find This Useful

This discussion may be of interest to individuals working on DIY heating elements, those exploring the thermal properties of resistance wire, or anyone considering the design of low-power heating applications.

John Galt
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Temperature generated by resistance wire??

I've got a problem I need some help on.

I have 9.42 inches of a semi-coiled (the coils are horizantal, not vertical like wrapping wire around a pencil) design resistance wire rated at 4.701 ohms/foot. I have a 12vac power source with a 600ma rating. Is it possible to calculate what temperature is generated by the wire? Let's consider the increased resistance of the wire with increased temperature as negligible.

Thanks all you smarties :biggrin:
 
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John Galt said:
I've got a problem I need some help on.

I have 9.42 inches of a semi-coiled (the coils are horizantal, not vertical like wrapping wire around a pencil) design resistance wire rated at 4.701 ohms/foot. I have a 12vac power source with a 600ma rating. Is it possible to calculate what temperature is generated by the wire? Let's consider the increased resistance of the wire with increased temperature as negligible.

Thanks all you smarties :biggrin:
I'm assuming the form of winding is irrelevant to the problem since you know its resistance is 3.96 ohms. Before trying to calculate temperature, you have a power supply problem; you won't come close to supplying enough current to drive this fully. If you have a good supply that current-limits cleanly, and assuming your 12Vac is rms, then the power generated is 12V*0.6A=7.2W. If it's just a transformer or something like that, then the output voltage will sag and you don't know how a priori how much power you'll get. Measuring it would be the best bet.

Is the wire temperature really important, or are you trying to heat something up?
 
The power supply is from a 12vac transformer rated at .6A. The transformer is just one of those 'plug into the wall' types. I'm embedding the resistance wire in ceramic to make a heating element. The temperature I'm shooting for would be enough to light a cigarette upon contact with the clay. The manufacturer of the resistance wire says that about half the amps are needed to heat the same length of wire to a specific temperature if it is coiled rather than strait, which is the only reason I mentioned the shape of the wire. How much should I expect the voltage to sag? I wasn't expecting that.

The accuracy tolerance of the temperature needed is very high. I don't need any specific temperature, just something hot and consistent.

Thanks for the speedy reply :)
 
Hmm, I'm not happy designing a cigarette lighter that's going to give you lung cancer You could figure out your transformer's internal source impedance to know what it will do with that load, but it's not worth the trouble, it won't do the job.

You're going to need to put time in on some technical work here, are you willing to read up on heat transfer, etc.? For instance, cherry red is about 1500F. You need to estimate/calculate the heat losses of your device to figure out the heat input needed to reach that surface temp. The dominant losses are a) radiation and b) conduction to air and to the mount, whatever it is. Also the temperature dependence of wire resistance will not be negligible.

Alternately, build your lighter, borrow a big power supply with a knob, and turn it 'til you get what you want. Or light your stogies with a match...
 
Oops, I forgot that inductance results in a coiled wire with current going through it, hence the voltage sag.

I like your idea of the power regulating knob. I didn't want to purchase a voltmeter or ammeter, but it's possible to find one for cheap I suppose.

Edit* I understand that heat losses occur and that in the temperatures I am working with the resistance will only increase by a factor of 3% or so, making it negligible considering my high accuracy tolerance. I suppose experimenting with a couple different voltage and ampere rated transformers would be best. This project isn't rocket science...lol, so it must not be treated as such.
 
Last edited:
John Galt said:
Oops, I forgot that inductance results in a coiled wire with current going through it, hence the voltage sag.

I like your idea of the power regulating knob. I didn't want to purchase a voltmeter or ammeter, but it's possible to find one for cheap I suppose.

Edit* I understand that heat losses occur and that in the temperatures I am working with the resistance will only increase by a factor of 3% or so, making it negligible considering my high accuracy tolerance. I suppose experimenting with a couple different voltage and ampere rated transformers would be best. This project isn't rocket science...lol, so it must not be treated as such.
Inductance shouldn't be a problem at low frequency (60 Hz). I Googled nichrome wire (I'm guessing that's what you have) and found this web site. 28AWG matches your resistance/foot. Looks like about 3A will get you a dull red, about 3-1/2A for a nice cherry red, in a straight line (probably in still air), about half that for a coil. For a really tight coil like a cigarette lighter you'll probably need even less. So 1 to 1.5A across your 4 ohm wire is 4 to 6 V.
If the website is accurate, then a 5V supply that can source a couple of amps will do the job for you.
 

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