Temperature increase by light absorption

AI Thread Summary
The discussion centers on calculating the temperature rise in a crystal that absorbs light and releases excess energy as heat. Key factors influencing this calculation include the power of the radiated light, the reflection coefficient, and the heat capacity of the crystal. For a black body, the relationship between energy and temperature change can be expressed as ΔT = W*t/C. In a general case, the absorbed energy can be calculated using the formula Eabsorbed = (1-ρ)∫W(t)*dt, leading to ΔT = (1-ρ)/C * ∫W(t)*dt. Understanding these variables is crucial for accurate temperature rise predictions.
sciphys1
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Hi,

I have a question. If a crystal absorbs light and the absorption process leads to some excess energy being released as heat . Can one calculate the temperature rise or an experiment would most certainly need to be done? Apart from the heat capacity of the crystal before light absorption ,what else would one need to know? Any discussion on this would be highly appreciated.

Thanks.

Sciphys1
 
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It will depend upon the power of radiated light, reflection coefficient and heat capacity, if you consider the case of a black body, then the radiated energy is W*t, ΔT = W*t/C, if you want a general case, then the absorbed energy Eabsorbed = (1-ρ)∫W(t)*dt, ρ is the reflection coefficient ΔT = (1-ρ)/C * ∫W(t)*dt
 
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