Temperature Question (answ=neg#-?)

  • Thread starter Thread starter grantP
  • Start date Start date
  • Tags Tags
    Temperature
AI Thread Summary
A .03kg piece of iron loses energy when heated to 100 degrees Celsius and then dropped into cool water, cooling down to 30 degrees Celsius. The calculation shows a change in energy of -945J, indicating energy loss. The negative sign signifies the direction of energy transfer, meaning the iron lost 945J to the water. The final answer should be presented as 945J to reflect the total energy lost. This understanding clarifies the interpretation of negative values in energy calculations.
grantP
Messages
19
Reaction score
0
[SOLVED] Temperature Question (answ=neg#-?)

Homework Statement


A .03kg piece of iron is heated to 100 degrees celsius and then dropped into cool water where the iron's temperature drops to 30 degrees celsuis. How many joules does it lose to the water?(Specific Heat Capacity of Iron=450J)

Homework Equations


change-in-energy=(SHC)(m)(Tf-Ti)

The Attempt at a Solution



change-in-energy=(450)(.03)(30-100)
=-945J
does it matter that my answer is a negative number?
 
Physics news on Phys.org
You found the change in energy, which is the final energy-the initial energy

the fact that it's negative implies what? Does that seem correct?
 
grantP said:
does it matter that my answer is a negative number?
Reread the phrasing of the question. (If the change in the amount of money in your wallet after playing poker is -$5, how much did you lose?)
 
ok so i think my answer should just simply be 945J instead of -945J because the negative implies that is what i lost, and evidently is exactly what was asked in the question!
is this thinking right?
 
Correct
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top