Temperature Required for Brass Plug and Iron Ring to Fit

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To determine the common temperature at which a brass plug will fit into an iron ring, the initial diameters at room temperature (20°C) are 8.755 cm for the plug and 8.745 cm for the ring. The coefficients of linear expansion are 10x10^-6 (°C)^-1 for brass and 12x10^-6 (°C)^-1 for iron. The problem requires calculating the temperature increase needed for the brass to expand sufficiently to fit into the iron ring. The calculations involve using the formula for linear expansion, which relates the change in diameter to the change in temperature. Assistance is needed for the specific calculations and methodology to arrive at the correct temperature.
Jayhawk1
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A brass plug is to be placed in a ring made of iron. At room temperature (20oC), the diameter of the plug is 8.755 cm and that of the inside of the ring is 8.745 cm. They must be brought to what common temperature (in Co) in order to fit? The coefficient of linear expansion for brass is 10x10-6(Co)-1 and that for iron is 12x10-6(Co)-1.

I don't know what to do with this... I know I have to subtract and divide some of these numbers, but I have no clue as to how to do it exactly. I need help please! Thank you.,
 
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Jayhawk1 said:
A brass plug is to be placed in a ring made of iron. At room temperature (20oC), the diameter of the plug is 8.755 cm and that of the inside of the ring is 8.745 cm. They must be brought to what common temperature (in Co) in order to fit? The coefficient of linear expansion for brass is 10x10-6(Co)-1 and that for iron is 12x10-6(Co)-1.

I don't know what to do with this... I know I have to subtract and divide some of these numbers, but I have no clue as to how to do it exactly. I need help please! Thank you.,

https://www.physicsforums.com/showthread.php?p=543205#post543205
 
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I still am confused...

I need more help please.
 
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