Temperature Variation Coefficient

AI Thread Summary
The discussion focuses on determining the unit of the temperature variation coefficient, Ψ, in a system involving water and room temperature. The equation presented indicates that Ψ relates the change in temperature over time to the difference between the system's temperature and the room temperature. There is confusion regarding whether the unit should be degrees per second, as this is typically associated with angular velocity. It is clarified that temperature degrees and angle degrees are distinct units, which adds complexity to the interpretation. Ultimately, the conversation emphasizes the need for clarity in distinguishing between these units in the context of temperature variation.
Pochon
Messages
1
Reaction score
0

Homework Statement


What is the unit of the system-universe temperature variation coefficient?

The system is a container holding a mass of water. T
The universe I guess is the room temperature. Troom
t is time in seconds.
\Psi is the temperature variation coefficient.

Homework Equations


\DeltaT / \Deltat = \Psi(T - Troom)
\Psit = ln ((To - Troom) / (T - Troom))

The Attempt at a Solution


Since it is temperature over time I thought that it would be degrees per second? But that is angular velocity so I'm sure that's not it.
 
Physics news on Phys.org
Degrees that measure temperatures are different than degrees that measure angles. You may consider them to be entirely different units, even though it's the same word.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top