Tensile force in elevator problem

AI Thread Summary
The discussion revolves around calculating the tensions T1 and T2 in two strings supporting blocks in an accelerating elevator. The initial calculations provided were T1 = 2(ma + mg) and T2 = ma + mg, with the upper string expected to break first under sufficient acceleration. When considering the scenario where the elevator cable breaks, it was clarified that the system would enter free fall, resulting in T1 and T2 both equaling zero. The participants confirmed the understanding of the physics involved, particularly the effects of acceleration and free fall on tension in the strings.
bdh2991
Messages
102
Reaction score
0

Homework Statement


Two blocks, each of mass m are hung from the ceiling of an elevator as in the figure below. The elevator has an upward acceleration a. The strings have negligible mass.

http://imageshack.us/a/img856/2241/5p031.gif

Find the tensions T1 and T2 in terms of m, a, and g.

Which string would break first if a was sufficient large?

What are the tensions if the cable supporting the elevator breaks?



Homework Equations



F = ma

The Attempt at a Solution



My answers were:

T1 = 2(ma + mg)
T2 = ma + mg

the upper string would break first

T1 = 2(-ma + mg)
T2 = -ma + mg

can anyone please check my work and see if these answers are correct? thanks
 
Last edited by a moderator:
Physics news on Phys.org
Looks good for the first part. For the second part, the elevator could no longer be accelerating up, since only gravity firce would be acting down. The elevator and its contents would be in free fall. In free fall, what is the acceleration? Redo your calcs for the tensions.
 
PhanthomJay said:
Looks good for the first part. For the second part, the elevator could no longer be accelerating up, since only gravity firce would be acting down. The elevator and its contents would be in free fall. In free fall, what is the acceleration? Redo your calcs for the tensions.

So...if the object is in free fall that would mean:

T1 = 0 and T2 = 0?
 
Thank you for the help. Makes sense now that i think about it the right way
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top