How Do You Calculate the Mass of the Second Penguin?

  • Thread starter Thread starter Angry Citizen
  • Start date Start date
  • Tags Tags
    Force Tension
AI Thread Summary
To calculate the mass of the second penguin, start by drawing free body diagrams for the entire system and the first two penguins. The equations of motion can be set up using F=MA, treating all four penguins as a single mass since they move uniformly. Tension forces, such as t2 and t4, should be considered as pulling forces acting away from the objects they connect. Isolate the penguins to determine the tensile forces in the ropes and solve the resulting equations for the unknown mass. Understanding the direction of tension forces is crucial for accurately setting up the problem.
Angry Citizen
Messages
607
Reaction score
0

Homework Statement



Four penguins are being playfully pulled along frictionless ice by a curator. The masses of three penguins and the tension in two of the cords are m1 = 12 kg, m3 = 15 kg, m4 = 20 kg, t2 = 111 N, and t4 = 222 N. Find the mass of the second penguin.

Note: t2 is the tension between the second penguin and the third penguin, and t4 is the tension between the curator and the fourth penguin.


Homework Equations



F=MA

The Attempt at a Solution



I don't know how to set up this problem. It is useless to separate it into its components using F=MA, since the acceleration is not given nor can it be derived without the second mass. I don't really understand the tension force very well since it runs counterintuitive to my sense of a free-body diagram. Can anyone clue me in on how to start?
 
Physics news on Phys.org
Draw a free body diagram of the entire system: 'm2' and 'a' will be unknown variables. Then draw a free body digram of the first 2 penguins together: 'm2' and 'a' will be unknowmnvariables, and T1 won't matter in this FBD, because it is internal in this free body diagram. Solve the 2 equations for the 2 unknowns.
 
In the free body diagram, when drawing the tension force in t4, in which direction does it point? And all four penguins can be treated as a single 'particle' given that they move uniformly in the same direction, correct?
 
Angry Citizen said:
In the free body diagram, when drawing the tension force in t4, in which direction does it point? And all four penguins can be treated as a single 'particle' given that they move uniformly in the same direction, correct?
Yes, they can be treated as one large mass since they move together with the same speed ans acceleration and displacement. Tension "pulling" forces always pull away from the objects on which they act. Then you must isolate the penguins to determine the tensile forces in the rope.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top