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A bag of cement of weight Fg hangs from three wires as shown in the attached diagram. Two of the wires make angles theta1 and theta2 with the horizontal. If the system were in equilibrium, show that the tension in the left hand wire is:

T1 = Fgcostheta2/sin(theta 1 + theta2)

Ok, I get that T3 = Fg. I drew a triangle of all the tension forces but that didn't help. Just seems like an odd type of question.

Any help, clues, or suggestions?

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# Homework Help: Tension bag Problem

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