Tension in a pulley system pulled at an angle

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In a pulley system where the angle is 90 degrees, the tension is not simply 2T, as the configuration alters the distribution of forces. The tension would be less than 2T due to the asymmetry introduced by the angle. Making the pulley fixed can change the dynamics, potentially affecting how forces are transmitted through the system. The sideways force from the right rope could indeed exert a lateral pull on the mass. Creating a free body diagram would help visualize these forces and their interactions within the system.
erensatik
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Homework Statement
The system is in equilibrium. What is the tension in the bottom rope in the setup below? Neglect the mass of the rope and the pulley.
Relevant Equations
F=ma
This problem just came to my mind when thinking on another problem. Does the tension is just 2T as it is if the angle "a" is 90 degrees? It seems not to me. In a "normal"( I don't really know what is the right word for that) situation, the tension is would be 2T at the line in the middle of two strings and would be symmetric. So it should be less than that I guess. That's all I can think of and I am not sure. Please help me out.
One last thing I need to ask is that does making the pulley fixed makes a difference? I have no idea what would be the difference.
 

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I don't think you should be showing the vertical rope as straight vertical. Do you think that the sideways force from the right rope might pull the mass to the right a bit?
 
Do you know how to create a free body diagram of that loaded pulley?
 
Lnewqban said:
Do you know how to create a free body diagram of that loaded pulley?
totally got it, saying that is enough. Thanks for the help
 
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