A 36.0 kg uniform beam is attached to a wall with a hinge while its far end is supported by a cable such that the beam is horizontal.
If the angle between the beam and the cable is θ = 69.0° what is the tension in the cable?
Unknown other than basic trigonometry
The Attempt at a Solution
I tried using simple trigonometry; Cos(69)=(36*g)/h, but to no avail. I believe the reason it didn't work to be because the cable is not attached to the bar's center of mass, but I've no idea how to correct this. A point in the right direction would be greatly appreciated!
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