Tension in String for 0.25 kg Ball Revolving at 2 Hz

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To calculate the tension in the string for a 0.25 kg ball revolving at 2 Hz, use the formula T = m(v^2)/R, where v is the velocity derived from frequency. The ball's frequency of 2 Hz indicates it completes two revolutions per second, which affects the velocity calculation. Velocity can be found using v = 2πR * frequency, where R is the radius of 0.5 m. The tension in the string acts as the centripetal force required for circular motion. A step-by-step example can clarify the calculations further.
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A 0.25-kg ball attached to a string is rotating in a horizontal circle of radius 0.5 m. If the ball revolves twice every second, what is the tension in the string?
 
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Whyy

Why Wont Anoyboyd Help Me!
 
T (tension)= m*(v^2)/R
And v (speed) You can find from frequency!?
 
so do you just plug the numbers into that formula and if it revolves twice every second does that effect the problem.
 
You should represent velocity throgh the frequency
Or You can find velocity through v=s/t
 
do you mind doing out the problem because i am confused.like a step by step example..thank you so much Yegor
 
1.The tension in the rope/wire is a centripetal force.Which formula giving the centripetal force would be best to use in this case?

Daniel.
 
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