A solid uniform 45.0 kg ball of radius 0.16 m is supported against a vertical, frictionless wall using a thin 0.30 m wire of negligible mass. Find the tension in the wire.
Sinθ = opposite/hypotenuse
Cosθ = (m*g)/T or T/(m*g); I'm not sure
The Attempt at a Solution
The angle is sin^(-1)(r/(r+0.30 m) = 19.471 degrees.
My textbook probably uses Cosθ = (m*g)/T to find the tension because that gives their answer OF 470.0 N. But, how can the force of the tension be greater than mg? I intuitively thought that maximum tension would be when θ = 0° and decrease to 0.00 N as θ goes to 90°.
This doesn't make any sense to me.