- #1

- 498

- 12

## Homework Statement

A solid uniform 45.0 kg ball of radius 0.16 m is supported against a vertical, frictionless wall using a thin 0.30 m wire of negligible mass. Find the tension in the wire.

## Homework Equations

Sinθ = opposite/hypotenuse

Cosθ = (m*g)/T or T/(m*g); I'm not sure

## The Attempt at a Solution

The angle is sin^(-1)(r/(r+0.30 m) = 19.471 degrees.

My textbook probably uses Cosθ = (m*g)/T to find the tension because that gives their answer OF 470.0 N. But, how can the force of the tension be greater than mg? I intuitively thought that maximum tension would be when θ = 0° and decrease to 0.00 N as θ goes to 90°.

This doesn't make any sense to me.