Tension or Compression: Determining the Forces on a Hinged Support Point

AI Thread Summary
In the discussion, participants analyze a static equilibrium problem involving two rods supporting a weight. They clarify that compression refers to an inward force on the rod, while tension refers to an outward force. A suggestion is made to apply Newton's second law at the junction where the rods meet to determine the forces acting on them. Participants express difficulty in solving the problem and seek guidance on how to proceed. The conversation emphasizes understanding the concepts of tension and compression in the context of static forces.
tonald
Messages
6
Reaction score
0
The figure shows a weight W supported by two light rigid rods P and Q. The rods are smoothly hinged to the wall and mounted in the same vertical plane. Which rod is in compression , is in tension?
 

Attachments

  • FZ.jpg
    FZ.jpg
    5.7 KB · Views: 440
Physics news on Phys.org
Show what you've done so far and where you got stuck.
 
I can't think anything...
Actually, compression means the force towards the wall?
Can you give me some hints to start with the question...
 
"Compression" means that there's an inward force pushing on the ends of the rod; "tension" means there's an outward force on the rod.

This is a problem in static equilibrium.
 
Can you show me how to solve this question...
I really can't solve it
or please give me some hints to guide me to finish it ,thanks...
 
Welcome to PF!

tonald said:
The figure shows a weight W supported by two light rigid rods P and Q. The rods are smoothly hinged to the wall and mounted in the same vertical plane. Which rod is in compression , is in tension?

Hi tonald! Welcome to PF! :smile:

Hint: use good ol' Newton's second law on the peg (or whatever it is) where the two rods meet …

it isn't moving, and there are three forces on it, so they … ? :smile:
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top