- #1
aliciaw0
- 17
- 0
A 68.0 Kg tightrope walker stands at the center of a rope. The rope supports are 10 m apart and the rope sags 8.00 degrees at each end. The tightrope walker crouches down, then leaps straight up with an acceleration of 8.10 m/s^2 to catch a passing trapeze.
What is the tension in the rope as he jumps?
i guess i just don't understand the question in general.
y: 2Tcos(8)-Fg=68.0kg*8.10m/s/s
x: 2Tsin(8)=ma=0
What is the tension in the rope as he jumps?
i guess i just don't understand the question in general.
y: 2Tcos(8)-Fg=68.0kg*8.10m/s/s
x: 2Tsin(8)=ma=0