1. The problem statement, all variables and given/known data Each box weighs 40 lbs, the angles are measured relative to the horizontal. The surfaces are smooth (no friction). Determine the tension in rope A and the normal force exerted by box B by the incline. 2. Relevant equations W = mg ΣF_x = 0 ΣF_y = 0 3. The attempt at a solution I found the tension of rope C and then normal force exerted on box D by setting up a system of equations. Solved, the tension equals 15.1 lb, and the normal force exerted is 33.1 lb. Now I'm having trouble determining the normal force of B and the tension of rope A. Attempting the solution: ΣF_x = 0 = 15.1*cos(45) + N*sin(70) - T_a*cos(70) ΣF_y = 0 = -15.1*sin(45) + N*cos(70) - T_a*sin(70) - 40 Solved using systems of equations, we found the normal force to be .0015lb (unreasonable), and the tension of A to be 31.2 lb (also unreasonable?). I can't figure out where I went wrong to get this bad answer. Anyone spot some mistakes? Thanks.