# Terminal velocity

Hello,

I am finishing my IB internal assessment in physics. I have thrown four balls (with different masses, 400,450,475,500 grams) from a height, which is approximately 23 meters. My teacher told me to set up a graph which showed mass vs. vt^2.

He said that the inverse of M= ((1/2)(p)(C_d)(A) / (g)) x v^2 is the slope. I have problems making anything of this. Can someone please explain how to get up with the equation above?

Thank you very much!

## Answers and Replies

The purpose of the investigation was to see how terminal velocity acts on objects with different weight.

PeterDonis
Mentor
2020 Award
Moderator's note: moved to homework forum.

PeterDonis
Mentor
2020 Award
The purpose of the investigation was to see how terminal velocity acts on objects with different weight.

What is the formula for terminal velocity?

What is the formula for terminal velocity?

v_terminal = (Sqrt(2mg)/(C*p_air*A))

haruspex
Science Advisor
Homework Helper
Gold Member
2020 Award
He said that the inverse of M= ((1/2)(p)(C_d)(A) / (g)) x v^2 is the slope.
That is not the slope. The slope is either the ((1/2)(p)(C_d)(A) / (g)) part or its inverse. Which of those depends on how you assign mass and v2 to the x and y axes.