What is the Maximum Acceleration a Man Can Achieve Pushing a Fully Loaded Cart?

AI Thread Summary
A man can achieve a maximum acceleration of 10 m/s² when pushing an empty 20kg cart. When the cart is filled to a total weight of 100kg, the acceleration will decrease due to the increased mass. Using Newton's second law (F=ma), the force exerted by the man remains constant, but the acceleration is inversely proportional to mass. Therefore, the acceleration of the full cart can be calculated as 2 m/s². The discussion highlights the relationship between mass and acceleration in physics.
deluxenathan
Messages
2
Reaction score
0
A man pushes an empty 20kg cart as hard as he can and the cart accelerates at 10m/s. The cart is then filled so that the weight is 100kg. How much acceleration can the man achieve pushing the full cart?

(Show all your working)
 
Physics news on Phys.org
Yah sorry, we're not stupid. Show your work. We're not here to do your homework for you.
 
LMAO! Funniest post (and reply) ever. Cracking up like there's no tomorrow :smile: !
 

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

Need Physics Help: Acceleration of a Cart w/ Working Out
Replies
2
Views
1K
A cart and pulley problem with a twist
Replies
6
Views
3K
Maximum Acceleration of sliding crates
Replies
6
Views
2K
What is the maximum acceleration in m/s^2 the cart can undergo
Replies
7
Views
2K
Help with a Friction Question: Maximum mass a Man can Push
Replies
12
Views
6K
Mechanical Advantage and What it really means (question inside)
Replies
2
Views
2K
How Can I Solve These Physics Problems for My Test Tomorrow?
Replies
9
Views
4K
Determine the magnitude of the normal force exerted by the table
Replies
5
Views
6K
Maximum Acceleration and Coefficient of Friction
Replies
3
Views
12K
What Is the Maximum Force Mary Can Apply Without Roberto Sliding Off the Sled?
Replies
3
Views
5K

Hot Threads

Recent Insights

Back
Top