The applied and friction forces of a particle

AI Thread Summary
A particle of mass 14kg slides along a wire inclined at 60 degrees to the horizontal, with a coefficient of dynamic friction of 0.6. The applied force P, acting parallel to the X-axis, must overcome both the frictional force and provide the necessary acceleration of 2 m/s². Discussions highlight confusion regarding the direction of forces, particularly the normal force and friction, emphasizing that the wire is horizontal while inclined at an angle. The correct calculation of P is debated, with some attempts yielding results around 208N, while the problem states it should be 220.8N. Clarification on the friction's nature—between the particle and the wire—is essential for accurate problem-solving.
Edd988
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Homework Statement


A particle of mass 14kg, slides along a straight wire in a horizontal plane. The coefficient of dynamic friction u=0.6 The equation of the line of the wire is y=3√x so that the angle between the wire and the X-axis is 60 degrees.

The particle accelerates with a constant acceleration whose magnitude is a=2 At time t=3s the particle is at A. The acceleration is produced by an applied force P acting parallel to the X-axis.

(b) Show that the magnitude of P is P = 220.8 Newtons

Homework Equations


F=ma
F=UR (U is coefficient of dynamic friction and R is R=mgcos(x))

The Attempt at a Solution



P-F=ma
F=UR
P=ma + F
F=0.6*mgcos(theta) = 41.202
P=14*2 + 41.202
P=69.202
[/B]
 
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A few problems there.
P and a are not in the same direction, so P-F=ma is wrong.
The wire is horizontal, so mg cos(theta) is wrong.
What are all the forces on the particle, and in what directions do they act?
 
The normal force acts perpendicular to the wire, the gravity force acts downward to the particle, the applied force will push the particle, and the friction force will act in the opposite way.
I though the plane was horizontal and the angle between the wire and the plane is 60 degree?
 
Edd988 said:
The normal force acts perpendicular to the wire, the gravity force acts downward to the particle, the applied force will push the particle, and the friction force will act in the opposite way.
I though the plane was horizontal and the angle between the wire and the plane is 60 degree?

The wire is also horizontal, it makes 60 degree angle with the x axis.
 
I guess, the wire is at 60 degree from horizontal.
 
Edd988 said:
The normal force acts perpendicular to the wire
Right, but that leaves a range of possibilities for the direction.
Edd988 said:
the applied force will push the particle
Yes, but in which direction does P act in relation to (a) the horizontal plane and (b) the x-axis (c) the wire?
Edd988 said:
friction force will act in the opposite way
Opposite to what exactly? I.e., which direction is the force of friction in relation to (a) the horizontal plane and (b) the x-axis (c) the wire?
 
jatin9953 said:
I guess, the wire is at 60 degree from horizontal.
That's not what it says:
Edd988 said:
along a straight wire in a horizontal plane
 
I tried it, with conservation of energy and got the answer close to 208N
 
jatin9953 said:
I tried it, with conservation of energy and got the answer close to 208N
I get a rather larger result. The tricky part is calculating the normal force correctly.
 
  • #10
The result given in the problem is obtained if friction exist between the ground and the object only. The object slides along the wire, on the ground.
 
  • #11
ehild said:
The result given in the problem is obtained if friction exist between the ground and the object only. The object slides along the wire, on the ground.
Hmm... there's nothing in the OP about a ground, and it sounds like the friction is between particle and wire. Edd, have you stated the problem exactly as given to you?
 
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