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The Arrhenius equation question

  1. Mar 6, 2013 #1
    When finding the activation energy, which equation is the correct one:

    ln(k2/k1)=-Ea/R * (1/T2-1/T1)
    ln(k1/k2)=Ea/R * (1/T2-1/T1)

    Notice k1/k2 in the second equation. As well as the -Ea instead of Ea

  2. jcsd
  3. Mar 6, 2013 #2
    Aren't they both the same? ln(a/b) = ln a - ln b = -(ln b - ln a) = -ln(b/a) ?
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