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here's what I did: i solved for velocity=6.626*10^-34J/(9.11*10^-31kg)(3.31*10^-10)

v=2.1974*10^-74

and i tried to gain the percent by dividing the speed of light by velocity.

where did i go wrong?

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- Thread starter plstevens
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In summary, the de Broglie wavelength is a concept in quantum mechanics that describes the wavelength associated with a moving particle. It can be calculated using the equation λ = h/mv, and it shows that all particles have wave-like properties. This concept is related to the Heisenberg uncertainty principle, and can be observed in everyday objects, although it is typically too small to be detected.

- #1

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here's what I did: i solved for velocity=6.626*10^-34J/(9.11*10^-31kg)(3.31*10^-10)

v=2.1974*10^-74

and i tried to gain the percent by dividing the speed of light by velocity.

where did i go wrong?

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- #2

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I get v = (0.00732)c

- #3

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plstevens said:

here's what I did: i solved for velocity=6.626*10^-34J/(9.11*10^-31kg)(3.31*10^-10)

v=2.1974*10^-74

and i tried to gain the percent by dividing the speed of light by velocity.

where did i go wrong?

how did u calculate... watch the exponents first...

the magnitude is 10^7 m/s...

[tex]\frac{6}{9\times3}\times\frac{10^{-34}}{10^{-31}\times10^{-10}}\approx\frac{2}{9}10^7 m/s[/tex]

this suggest us that it is better to treat the electron relativistically if we want to penetrate deep in its properties...

regards

marco

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thanx Dirac :)

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- #6

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For the velocity of the particle, I get:

[tex] v = 2.197 \times 10^6 \ \ \ \frac{\textrm{m}}{\textrm{s}} [/tex]

The question asks how fast the particle is moving

[tex] \frac{v}{c} = \frac{2.197 \times 10^6 \ \ \ \textrm{m/s}}{3.00 \times 10^8 \ \ \ \textrm{m/s}} = 0.00732 [/tex]

So, expressed in units of the speed of light, the velocity is

[tex] v = 0.00732c [/tex]

The particle is moving at 0.00732 times the speed of light. Obviously, as a percentage, that's 0.732%. So I guess if you wanted to, you could say that the particle is moving at 0.732% of the speed of light. It's a completely equivalent statement though. It doesn't add any extra meaning.

The de Broglie wavelength is a concept in quantum mechanics that describes the wavelength associated with a moving particle. It is named after French physicist Louis de Broglie.

The de Broglie wavelength can be calculated using the equation λ = h/mv, where λ is the de Broglie wavelength, h is Planck's constant, m is the mass of the particle, and v is its velocity.

The de Broglie wavelength is significant because it shows that all particles, including matter, have wave-like properties. This concept is a key aspect of quantum mechanics and helps explain the behavior of particles at the subatomic level.

The de Broglie wavelength is related to the Heisenberg uncertainty principle, which states that it is impossible to know both the position and momentum of a particle with absolute certainty. This is because the de Broglie wavelength and momentum are inversely proportional, meaning that the more accurately we know the momentum of a particle, the less accurately we know its position.

Yes, the de Broglie wavelength can be observed in everyday objects, but it is typically too small to be detected. However, in certain experiments, such as the double-slit experiment, the wave-like behavior of particles can be observed, including the de Broglie wavelength. This shows that the concept applies not just to subatomic particles, but to all matter.

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