The Doppler Effect of police car

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SUMMARY

The discussion centers on calculating the velocity required for a police car's Doppler effect to shift a red light (700 nm) to a green light (500 nm). Using the formula (V_rad/c) = Δλ/λ_o, the calculated velocity is approximately -0.2857c, indicating that the car is approaching the light source. The negative value signifies a blue shift, confirming the car's motion towards the light rather than away from it. This analysis clarifies the relationship between light wavelength shifts and relative motion in the context of the Doppler effect.

PREREQUISITES
  • Doppler Effect principles
  • Understanding of wavelength and frequency
  • Basic algebra and manipulation of equations
  • Familiarity with the speed of light (c = 3 x 10^5 km/s)
NEXT STEPS
  • Study the mathematical derivation of the Doppler Effect for light
  • Explore applications of the Doppler Effect in astronomy
  • Learn about redshift and blueshift in astrophysical contexts
  • Investigate the implications of relativistic speeds on light perception
USEFUL FOR

Physics students, educators, and anyone interested in the applications of the Doppler Effect in real-world scenarios, particularly in relation to motion and light.

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Homework Statement


There is a classic story (likely apocryphal) about an astronomer who was caught by a policeman for running a red light. The astronomer went to court and pleaded innocent, saying that the motion of his car made the red light (with a wavelength around 700 nm) shift to a green color (with a wavelength around 500 nm) due to the Doppler shift. The judge said something like “OK, you’re innocent of running a red light, but by your own testimony I am convicting you of speeding!” How fast would the astronomer have to have been speeding for his story to have been true? That is, calculate the velocity needed for the claimed color shift to be true. [express this velocity as a fraction of the speed of light.]

Homework Equations


Given: (V_rad/c)=Δλ/λ_o

The Attempt at a Solution



(500nm-700nm)/700nm=V_rad/(3x10^5km/s)
V_rad = -85714.29km/s
or
-.2857c

*********Am I doing my math correctly here? What is the significance of a negative value for V_rad? Do I just need to specify what direction I call positive and negative to eliminate the negative sign?
 
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You solved it correctly. The negative sign indicates a blue shift which means the car is approaching the light rather than moving away from it.
 
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Okay I thought that may have been a possibility as well but thank you very much vela for clearing it up for me!
 

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