The Effects of Resistance on Voltage

AI Thread Summary
In an open circuit, a voltmeter measures the EMF of a battery, but when the circuit closes, the voltage reading drops due to internal and external resistance. The discussion highlights that an ideal voltmeter, theoretically having infinite resistance, draws negligible current, allowing it to measure voltage without significantly affecting the circuit. It is emphasized that in practice, no voltmeter is truly ideal, and its resistance must be considered for accurate measurements. The potential difference is zero after the last resistor because every circuit element has some resistance, affecting voltage drop and current according to Ohm's Law. Understanding these principles helps clarify the relationship between voltage, resistance, and circuit behavior.
Mykhalo P
Messages
4
Reaction score
0
In an open circuit, a voltmeter in parallel to a battery measures the EMF. Once the circuit is closed, the measured voltage drops due to both the internal and the external resistance. My question is how can the initial resistor not affect the voltage the voltmeter measures?

Additionally,

Because an ideal voltmeter has infinite resistance, how can a voltmeter measure voltage without the electrons from the current? It's like, how can I measure the potential energy of a ball without the ball?

Also, if voltage is like potential energy, then why does potential difference equal to zero after it passes the last resistor, and not when it reaches the end of the wire?

I'm sorry that these questions are basic. I just hope to gain a decent understanding of the material. Thank you to anybody who is so kind as to help me out.
 
Engineering news on Phys.org
Hi Mykhalo, :welcome:
Mykhalo P said:
My question is how can the initial resistor not affect the voltage the voltmeter measures?
Not a very clear question. Could you re-phrase ?
Mykhalo P said:
Because an ideal voltmeter has infinite resistance, how can a voltmeter measure voltage without the electrons from the current?
It's possible: if you use an adjustable voltage source and let it produce the exact same voltage, a meter in between the two voltage sources should show no current.
It's like, how can I measure the potential energy of a ball without the ball?
Gravitational potential energy ? Measure the height and multiply by ##mg## ?

Mykhalo P said:
Also, if voltage is like potential energy, then why does potential difference equal to zero after it passes the last resistor, and not when it reaches the end of the wire?
That's a practical consideration: we assume the wire resistance can be ignored (i.e. set to zero for all practical purposes, so there is no voltage drop over the wire). Doesn't work for very low resistances !
 
Mykhalo P said:
Because an ideal voltmeter has infinite resistance, how can a voltmeter measure voltage without the electrons from the current?
It can't. Ideal voltmeter is a theoretical thing. Basically ideal things are theoretical. They do not exist. Practically,a voltmeter has (or should have) a "very high" resistance compared to anything in the circuit so that when connected in parallel with a component, it will draw a "negligible" current compared to actual currents in the circuits and hence, will not "disturb" the circuit parameters and it will not "load" the source. This negligible voltmeter current is often assumed to be zero practically, because we can neglect its effect in most of the circuits. In some circuits, the voltmeter resistance needs to be taken into account for extreme accuracy.
 
  • Like
Likes davenn and anorlunda
Mykhalo P said:
In an open circuit, a voltmeter in parallel to a battery measures the EMF. Once the circuit is closed, the measured voltage drops due to both the internal and the external resistance. My question is how can the initial resistor not affect the voltage the voltmeter measures?

Hi Mykhalo P

Have you learned about Ohm's Law? It's all about it. When the circuit is open, what is the resistance of the circuit? Plug it in Ohm's Law and find current. The voltmeter has a very big resistance in practice, such that it draws a small current, the one it needs to function properly. So ,what does this mean, in the context of measuring the voltage across a voltage source, in an open circuit? When you close the circuit, the total resistance changes. What does this imply for the same measurement?

Mykhalo P said:
Because an ideal voltmeter has infinite resistance, how can a voltmeter measure voltage without the electrons from the current? It's like, how can I measure the potential energy of a ball without the ball?

There is no such thing in practice as an ideal voltmeter. In theory, we say infinite resistance but this translates in practice, to a very big resistance. So, there is always some current drawn from the voltmeter, although very small.

Mykhalo P said:
Also, if voltage is like potential energy, then why does potential difference equal to zero after it passes the last resistor, and not when it reaches the end of the wire?

Every element of an electrical circuit has some resistance, at least small. This has direct consequences on the voltage drop and the current through the element (again Ohm's Law).
 
Last edited:
There seems to be a theme of people asking questions along the lines of "How can this thing I learned about in electricity be ideal? It doesn't make sense!" The simple answer is that nothing is perfect in the real world. You are being taught approximations and it's done for a good reason.

Try this for an exercise. Make up a simple circuit with a 10V source and a 10kOhm resistor. Figure out how much voltage a meter will read on the resistor if it does not have infinite impedance. Try it with a meter that has 1MOhm and 1GOhm internal resistance. Examine the results and see how they differ.

With that same circuit figure out the resistance of the wires that connect the circuit. Make all the wires 14AWG and 10cm long. Solve for the current in the circuit with the wire resistance added. Did the wire resistance make much difference?
 
Last edited:
  • Like
Likes anorlunda
Thread 'Weird near-field phenomenon I get in my EM simulation'
I recently made a basic simulation of wire antennas and I am not sure if the near field in my simulation is modeled correctly. One of the things that worry me is the fact that sometimes I see in my simulation "movements" in the near field that seems to be faster than the speed of wave propagation I defined (the speed of light in the simulation). Specifically I see "nodes" of low amplitude in the E field that are quickly "emitted" from the antenna and then slow down as they approach the far...
Hello dear reader, a brief introduction: Some 4 years ago someone started developing health related issues, apparently due to exposure to RF & ELF related frequencies and/or fields (Magnetic). This is currently becoming known as EHS. (Electromagnetic hypersensitivity is a claimed sensitivity to electromagnetic fields, to which adverse symptoms are attributed.) She experiences a deep burning sensation throughout her entire body, leaving her in pain and exhausted after a pulse has occurred...

Similar threads

Replies
8
Views
541
Replies
10
Views
2K
Replies
3
Views
1K
Replies
19
Views
3K
Replies
23
Views
5K
Back
Top