The Electric Field Due to a Charged Disk

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SUMMARY

The discussion centers on calculating the charge contained within a circular ring of width 30 µm on a charged disk with a radius of 1.80 cm and a total charge of Q = +2.15 × 106 e. The relevant equation used is E = σ/2ε(1 - z/√(z2 + R2)), where ε is the permittivity of free space (8.85 × 10-12 F/m). The participant calculated the charge within the ring to be approximately 3.15 × 1010 C, indicating a misunderstanding of the question's focus on charge rather than electric field.

PREREQUISITES
  • Understanding of electrostatics and charge distribution
  • Familiarity with the concept of electric fields and their equations
  • Knowledge of the permittivity of free space (ε)
  • Ability to perform calculations involving circular geometry
NEXT STEPS
  • Study the derivation and application of the electric field equation E = σ/2ε(1 - z/√(z2 + R2))
  • Learn how to calculate charge density (σ) from total charge (Q) and area
  • Explore the concept of charge distribution on non-uniform surfaces
  • Investigate the relationship between electric field and charge for different geometries
USEFUL FOR

Students and educators in physics, particularly those focusing on electrostatics, as well as anyone involved in problems related to electric fields and charge distributions.

brcole
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Homework Statement


A circular plastic disk with radius R = 1.80 cm has a uniformly distributed charge of Q = + 2.15 106 e on one face. A circular ring of width 30 µm is centered on that face, with the center of the ring at radius r = 0.50 cm. What charge is contained within the width of the ring?


Homework Equations


E=σ/2ε(1-z/√(z^2+R^2 ))


The Attempt at a Solution



e=8.85e-12
o= 2.15e6
z=.5 cm
r= 1.8
Ans=3.15 e10
 
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I don't see it as an electric field question. The question asks "what charge ...".
 

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