The Force Between Alpha Particles at 5.6E-15m

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The discussion centers on calculating the force between two alpha particles at a distance of 5.60E-15m using Coulomb's law. The user applies the formula F=ke*q1*q2/r^2 but consistently arrives at an incorrect result of 41.1N. The confusion arises regarding the charge of an alpha particle, which is +2e, not +1e. Clarification on the charge value is necessary to correct the calculations and achieve the accurate force measurement. Understanding the correct charge of alpha particles is crucial for resolving the calculation error.
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The nucleus of 8Be, which consists of 4 protons and 4 neutrons is very unstable and separates into two alpha particles (2 protons and 2 neutrons) what is the force between the two alpha particles if the distance is 5.60*10^-15m

I thought you would just use the formula F=ke*q1*q2/r^2

so I did that and I repeatedly have the wrong answer:

F= (8.99*10^9)(1.60*10^-19)(1.60*10^-19)/(5.60*10^-15)^2= 41.1N

Please tell what am I doing wrong?
 
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