The question is: A wheel is rolling smoothly on horizontal surface. There is a constant horizontal force of magnitude 10 N. Wheel has mass of 10 kg, and radius of 0.3 m. The accel. of its centre of mass has mag. of 0.6 m/s^2. I am asked to find frictional force in unit-vector notation. This is what i did: (10N) = f - (10kg)(9.8m/s^2)sin0* = (10kg)(0.6 m/s^2) (10N)-f = 6.0 -f = -4.0 Since there is clockwise angluar acccel the friction is a negative value. So my answer is f = (-4.00 N)i For part b it asks for the rotational inertia of the wheel about its centre of mass. This is what i've done so far: (-4 N)(0.3m) = I (-0.6m/s^2/0.3m) -1.20 = I(-2) I = 0.600 rad/s Am i on the right track?? Please help!!!