The fundmental thereom of line integrals

nameVoid
Messages
238
Reaction score
0
show that the line integral is indpendant of path and evaluate the integral on interval (0,1),(1,2)
int c 1-ye^{-x}dx+e^{-x}dy

can somone show me the procedure here looks like they just integrated 1-ye^(-x) on x to get 2/e I get a diffrent answer if I integrate e^(-x) on y same interval do I just find a potential function f with F = 1-ye^-x,e^-x
 
Last edited:
Physics news on Phys.org
hi nameVoid! :smile:

(have an integral: ∫ and try using the X2 icon just above the Reply box :wink:)
nameVoid said:
show that the line integral is indpendant of path

do I just find a potential function f with F = 1-ye^-x,e^-x

yes, you can either do that (there's a fairly obvious f :wink:),

or you can show that the curl is zero
and evaluate the integral on interval (0,1),(1,2)
int c 1-ye^{-x}dx+e^{-x}dy

can somone show me the procedure here looks like they just integrated 1-ye^(-x) on x to get 2/e I get a diffrent answer if I integrate e^(-x) on y same interval

if you get different answers, you've probably used the wrong limits …

show us your full calculations, and then we'll see what went wrong! :smile:
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top