Convergence of (n!)^2 / (kn)! for Positive Integers k: Ratio Test Explanation

  • Thread starter Thread starter remaan
  • Start date Start date
remaan
Messages
132
Reaction score
0
The hardest ever,,,

Homework Statement



40) for which positive intigers k is the following sries convergent:
(n!) ^2 / (kn)!

Homework Equations



using the ratio test the limit should be less than 1

The Attempt at a Solution



I tried the ratio test, but I got inifinty?
 
Physics news on Phys.org
Hi remaan! :smile:
remaan said:
for which positive intigers k is the following sries convergent:
(n!) ^2 / (kn)!

using the ratio test the limit should be less than 1

I tried the ratio test, but I got inifinty?

Hint: which is larger, (5!)2 or 10! ? :wink:
 


remaan said:
using the ratio test the limit should be less than 1
No -- it could be less than 1, but it doesn't have to. You're making some assumptions when you said that; what are they? (Or, I suppose you could have just made a mistake)

I tried the ratio test, but I got inifinty?
What does that tell you?
 


tiny-tim said:
Hi remaan! :smile:


Hint: which is larger, (5!)2 or 10! ? :wink:

Hi,

mm, 1o! is greater, but how can I benifit from this in finding K ??
 


Hurkyl said:
No -- it could be less than 1, but it doesn't have to. You're making some assumptions when you said that; what are they? (Or, I suppose you could have just made a mistake)

I mention that because the question says "positive intergers,"


What does that tell you?

It tells that the series is not alternating and I can't ( ratio test ) to find the k .
 


remaan said:
I can't ( ratio test ) to find the k .
Why not? The only time the ratio test is inconclusive is when the limit is 1, or doesn't exist, and for all possible values of k, you're not in either of those cases
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top