The law of conservation of energy

AI Thread Summary
To find mass (m) from the kinetic energy (Ek) and velocity (v) using the equation Ek=(1/2)mv^2, one can isolate m by manipulating the equation. Multiplying both sides by 2 eliminates the (1/2), allowing for easier calculations. Afterward, dividing Ek by v^2 yields the value of m. It's also valid to keep Ek on one side and isolate m without switching sides, simplifying the process. Understanding these algebraic manipulations is crucial for solving physics problems effectively.
cpaquette
Messages
2
Reaction score
0
I'm doing my physics homework and for one of the questions i have to find m(mass) when i already know Ek(kinetic energy) and v(velocity) with the equation Ek=(1/2)mv^2. I was just wondering if someone could tell me how to move the m in front of the equal sign and to move Ek to the other side.
 
Physics news on Phys.org
It is easier, and just as valid, to keep Ek on the side where it is, and to keep m on the side where it is. Just isolate the m, so it becomes the only variable on the RHS. For example, multiply both sides by 2, and that will get rid of that pesky (1/2) that's alongside the m. Then do something about the v^2 so that it disappears from the RHS.
 
Yeah, I gave up on trying to change sides and just added in the variables then divided Ek by 1/2 and v to get m but thanks for helping. I'll remember to multiply by 2 to get rid of the 1/2 next time.
 
cpaquette said:
added in the variables then divided Ek by 1/2 and v to get m
divided by v^2 I hope?

You could have swapped all on one side with everything on the other side right from the start, before thinking about doing any cancelling, if it was important that m be on the LHS rather than the RHS.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top