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- Problem Statement
- A .76 meter long wire runs horizontally and carries a current of 28 A from left to right. What would be the magnitude and direction of the minimum magnetic field to suspend the wire in mid air if the wire has a mass of 46.6 g/m

- Relevant Equations
- F=ILB

F=ILB

F=(48)(.76)B

F/36.48=B

I am stuck at how to find F, is there a different formula I am missing?

F=(48)(.76)B

F/36.48=B

I am stuck at how to find F, is there a different formula I am missing?