The method of Lagrange multipliers

yeland404
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Homework Statement


The problem of minimizing f(x1, x2) = x1^3
subject to
(x1 + 1)^3 = (x2 − 2)^2 is known to have a unique global solution. Use the method of Lagrange
multipliers to find it. You should deal with the issue of whether a constraint qualification holds.


Homework Equations



The problem of minimizing f(x) = 2x1^2+ x2^2+2x1*x2 -4x1-5x2+x3 subject to
2x1+x2+x3=0 is known to have a solution. Use the method of Lagrange
multipliers to find it. You should deal with the issue of whether a constraint qualification holds.

The Attempt at a Solution


I know for the queation be , the first step is to get the gradient of 2x1+x2+x3=0 then show is it nonzero everywhere, then use the Lagrange multiplier , but how about (x1 + 1)^3 = (x2 − 2)^2?
 
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First off, it doesn't make sense to say you're calculating the gradient of an equation. You calculate the gradient of a function.

You want to write the constraint in the form ##g(x_1,x_2) = c## where c is a constant. You then calculate ##\nabla g##.
 
What, exactly, is the question? You first say "minimize f(x_1,x_2)= x_1^3" but under "relevant equations" you say "minimize f(x)= 2x_1^2+ x_2^2+2x_1*x_2 -4x_1-5x_2+x_3". Are these two separate problems? Also how are x_1, x_2, and x^3 connected with x? Did you mean f(x_1, x_2, x_3)?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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