Entropy
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On the contrary, the burden of proof is on you. I'll humor you this time.
I'm not trying to prove it, I just claimed it might be possible.
You are either suggesting that it is only the object playing the part, and therefore objects farther away are always heavier dependant upon the distance, or you are saying there is a matter gradient evenly distributed throughout the universe.
In the first case you'll be at a loss to explain the state of stars far away. There are visible galaxies very far away which, under your theory, should have huge amounts of extra mass. Yet they contain stars who are burning rather weakly. On top of that, their rotational inertia doesen't allow for the huge amount of mass you are trying to give them. If all stars in a galaxy are redshifted, then they must all be heavier. Significantly.
As you know the redshift due to gravity with an observer away from the source is
where P_e is the gravitational potential energy.
The gravitational potential energy involved will be the the integral of the gravitational field produced by the body from the point the light is emmitted to the point it is recieved.
dr from to . We'll take to be at infinity to give you the greatest benefit of the doubt. Once you integrate and take the limit your formula will be:
Now let's take a star whose lyman alpha line has been shifted from a frequency of 25x10^12 to 8.3x10^12 (both in units of inverse seconds), which is far from the greatest shift to be seen, though it is sizable. Use a standard Sun type star that there are plenty of in the universe for your radius and you'll find that to create this red shift
M = 4x10^35, which is 100,000 times as heavy as our sun.
So in other words, to make this case that gravity is causing red shift, you are going to have to explain how everything half way to the edge of our vision is 100,000 times as heavy as everything near to us, and yet are visibly the same types of stars and do not show 100,000 times as much angular momentum.
Good luck
I won't bother with the matter gradient since you don't seem to feel matter is distributed evenly... and it's obviously just as invalid a hypothesis.
I was thinking of similar equations to the ones you have there today at school. As a small first step I planned on calculating how much red-shift a photon would experience traveling from the sun's surface to Earth. Just to get an idea of how much light is effected by a "normal" star's gravity. Unfortunately, I didn't have my physics book with me today so I wasn't able to look up the radius of the sun or the sun's mass. But I did manage to form some rough equations that would describe the lose in momentum of a photon over a distance with a decreasing gravitational pull as it travels away.
I'm only use to calculating marcoscopic objects with mass so dealing with the gravitational effects on light is new to me. But from what I've deduced so far from my equations is that the evidence seems to be tilting in your favor.
But, I'm not going to rule out that gravity couldn't in some way be effecting the way we see light. Gravity can do some strange things sometimes and with so many sources and such a vast universe there are bound to be unseen variables.
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