The relationship between hyperbolic and circular functions

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Hyperbolic functions, such as cosh x and sinh x, are analogous to circular functions like cos x and sin x due to their parametric representations of different geometric equations: circular functions represent the unit circle (x² + y² = 1), while hyperbolic functions represent a hyperbola (y² - x² = 1). This relationship becomes clearer when using complex numbers, which can show similarities between hyperbolas and circles. The discussion highlights that trigonometric identities can be transformed into hyperbolic identities by substituting the hyperbolic equivalents, with a notable sign change for products of two sine functions. This transformation is explained by Osborne's Rule, which provides a systematic way to relate the two types of functions. Understanding these connections can enhance comprehension of both circular and hyperbolic functions in calculus.
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Hello!
A book on calculus was introducing hyperbolic functions and pointed out that the identities such as cosh x and sinh x, etc. for hyperbolic functions were analogous to cos x and sin x for circular functions. I tried finding some internet sources explaining why this is so, but they tend to be overly complicated or unsatisfactory. Could someone point me in the direction of any recommended sources; or, perhaps, offer a brief explanation (presumably the explanation is not so brief!…)
Thanks in advance.
 
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Circular functions are parametritizations of the equation
x^2+y^2=1
Hyperbolic functions are parametritizations of the equation
y^2-x^2=1
so that explains the anaology
futher if complex numbers are used we see hyperbolas and circles as equivelent in some sense
 
lurflurf said:
Circular functions are parametritizations of the equation
x^2+y^2=1
Hyperbolic functions are parametritizations of the equation
y^2-x^2=1
Thanks ever so much lurflurf.
Because for any trig identities, apparently you simply substitute in the hyperbolic equivalent, changing the sign for a product of two sins. Is this simply a consequence of the minus sign in the above equation, and that the others remain 'unaffected'?
 
Yes!
That is called Osborne's Rule.
see
http://mathworld.wolfram.com/OsbornesRule.html
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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