The smallest coefficient of friction.

AI Thread Summary
The discussion revolves around determining the smallest coefficient of friction needed to prevent a small box from slipping on a larger box when both are subjected to an acceleration of 2.5 m/s². The frictional force is crucial as it allows the smaller box to move in tandem with the larger box. Participants emphasize that at the point of slippage, the maximum static frictional force equals the applied force. The user is encouraged to formulate an equation to represent this relationship. Understanding this concept is essential for solving the problem effectively.
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I just started with my Grade 12 Physics (Univeristy Level), and I would like some help (not necessarily an answer) but an explanation. Here it is:

A small box is resting on a larger box, which in turn sits on a table. When a horizontal force is applied to the larger box, both boxes accelerate together. The small box does not slip on the larger box.

If the acceleration of the pair of boxes has a magnitude of 2.5m/s/s, determine the smallest coefficient of friction between boxes that will prevent slippage.

I have drawn a free-body-diagram, and I have determined that the force of friction is what makes the small box move with the larger box. I do not have a teacher, other than for one period of the day for this course, so I will either have to wait to talk to him, or someone could pitch me something useful. Thanks.
 
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Welcome to the Forums,

You are quite right that it is the frictional force between the two boxes that prevents the smaller box moving. Now, you know that at the point of slippage the maximum static frictional force will equal the applied force. Can you write an equation to show this?
 
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