The Trouble with Normal Subgroups

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Homework Help Overview

The discussion revolves around finding an example of a group \( G \) and subgroups \( H \) and \( K \) such that \( H \) is normal in \( K \), \( K \) is normal in \( G \), but \( H \) is not normal in \( G \). The subject area is group theory, specifically focusing on properties of normal subgroups.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts various groups, particularly those of orders 8 and 16, to find suitable subgroups. They explore specific groups like the dihedral group \( D_8 \) and the quaternion group \( Q_8 \), but encounter challenges in finding a configuration where \( H \) is not normal in \( G \). Some participants suggest revisiting the dihedral group.

Discussion Status

The discussion includes multiple attempts and reflections on the properties of the groups being considered. While some participants suggest potential directions, there is no explicit consensus on a solution yet. The original poster expresses frustration with their attempts, indicating an ongoing exploration of the problem.

Contextual Notes

The original poster notes that they are particularly focused on groups of specific orders and the properties of their subgroups, which may impose constraints on their search for a valid example.

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[SOLVED] The Trouble with Normal Subgroups

Homework Statement


Find an example of a group [itex]G[/itex] and subgroups [itex]H[/itex] and [itex]K[/itex] such that [itex]H[/itex] is normal in [itex]K[/itex], [itex]K[/itex] is normal in [itex]G[/itex], but [itex]H[/itex] is not normal in [itex]G[/itex].


Homework Equations


None.


The Attempt at a Solution


I have many attempts.

In the beginning I was fixated on groups of orders 8 and 16, because I figured it would be easy to find nested subgroups with index 2 (that is, [itex][G:K] =2[/itex] and [itex][K<img src="/styles/physicsforums/xenforo/smilies/arghh.png" class="smilie" loading="lazy" alt=":H" title="Gah! :H" data-shortname=":H" />]=2[/itex]). Finding such groups is fairly easy, but finding them with [itex]H[/itex] not normal in [itex]G[/itex] has proved elusive.

Here are my false starts.

Attempt 1:
[itex]G=D_8[/itex], the dihedral group of order 8
[itex]K=<b>[/itex], the subgroup of order 4 generated by [itex]b[/itex]
[itex]H=<b^2>[/itex], the subgroup of order 2 generated by [itex]b^2[/itex]

Result: No good, [itex]H[/itex] is normal in [itex]G[/itex]

Attempt 2:
[itex]G=Q_8[/itex], the quaternionic group of order 8
[itex]K=\left<b\right>[/itex]
[itex]H=\left<b^2\right>[/itex]

I didn't even bother finishing this one. It became obvious that this attempt would fail for the same reason that the last one failed.

Attempt 3:
Here's where I tried to be more clever.

[itex]G=GL_2\left(\mathbb{Z}_3\right)[/itex]
[itex]K=SL_2\left(\mathbb{Z}_3\right)[/itex]
[itex]H=[/itex] the subgroup generated by the elements of order 4 in [itex]K[/itex] (this is a subgroup of order 8).

Once again, [itex]H[/itex] is normal in both [itex]K[/itex] and [itex]G[/itex].

I also did some goofing around with [itex]S_n[/itex] and [itex]A_n[/itex], but to no avail.

Little help?
 
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Try the dihedral group with order 8.
 
That was my first attempt. It didn't work.
 
Oh brother! I've got it. Like a dummy I was fixated on cyclic subgroups. I just considered a subgroup with two generators, and I got it.

FYI, [itex]\left<ab^2\right>[/itex] is normal in [itex]D_8[/itex], [itex]\left<a,b^2\right>[/itex] is normal in [itex]\left<ab^2\right>[/itex], but [itex]\left<ab^2\right>[/itex] is not normal in [itex]D_8[/itex], as [itex]b^{-1}ab^2b=abb^3=ab^4=a[/itex], which is not in [itex]\left<ab^2\right>[/itex].

So it was [itex]D_8[/itex] all along...
 

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