snoopies622
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As my knowledge of an electric field strength becomes more precise, what physical quantity becomes correspondingly less precisely known?
One can start with the Maxwell Lagrangian and show that there are three pairs of canonical conjugate field operatorsdextercioby said:There's no (direct) analogue of the "uncertainy principle" in quantum field theory.
tom.stoer said:
One can start with the Maxwell Lagrangian and show that there are three pairs of canonical conjugate field operators
[A_i(x),E_k(y)] = i\,\delta_{ik}\,\delta^{(3)}(x-y)
The problem is that we have a gauge theory, so there are unphysical d.o.f. which we have to eliminate; a first choice is the A°=0 gauge b/c for A° there's no E° due to the antisymmetry of the field strength tensor F and therefore ∂°A° is not present in F. Even then not all three i=1..3 are physical, we have to eliminate a second one to arrive at two physical polarizations.
Using Fourier decomposition one can introduce creation and annihilation operators for the fields; in terms of these operators it becomes clear that the canonically conjugate pair x,p is replaced by something like the Fourier modes of A and E, therefore one can derive an uncertainty principle for A(k) and E(k) where k is representing momentum space.