Thermodynamic constant volume process

AI Thread Summary
In a constant-volume process involving an ideal monatomic gas, 208 J of heat is transferred to the gas. The key equations for solving the problem include the relationship ΔU = W + Q, where W is the work done, and Q is the heat added. Since the volume is constant, the work done on the gas is zero, meaning the increase in internal energy equals the heat added. To find the final temperature, the heat capacity of the gas must be considered in relation to the change in temperature. Understanding these relationships is crucial for solving the homework questions effectively.
keevenh
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Homework Statement



In a constant-volume process, 208 J of energy is transferred by heat to 0.99 mol of an ideal monatomic gas initially at 290 K.
(a) Find the work done on the gas.

(b) Find the increase in internal energy of the gas.

(c) Find its final temperature.

I just don't know which equation to use and don't really know which direction to take.

Homework Equations



Pretty sure it involves ΔU=W+Q

The Attempt at a Solution


NIL
 
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Start by drawing a PV diagram of the process.

The work done is the area under the P-V curve.
The equations you want are the ideal gas law, something to relate internal energy to work and heat, and something to relate change in internal energy to temperature in a constant volume process.
 
keevenh said:

Homework Statement



In a constant-volume process, 208 J of energy is transferred by heat to 0.99 mol of an ideal monatomic gas initially at 290 K.
(a) Find the work done on the gas.

(b) Find the increase in internal energy of the gas.

(c) Find its final temperature.

I just don't know which equation to use and don't really know which direction to take.

Homework Equations



Pretty sure it involves ΔU=W+Q
Is there any work done? Plug that value into your equation.

Can you find the heat flow, Q? Plug that into your equation.

That will give you the change in internal energy.

How is Q related to change in temperature? (think: heat capacity of the gas).

AM
 

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