Thermodynamics: 2 Pistons connected by a rod

AI Thread Summary
The discussion focuses on a thermodynamics problem involving two pistons connected by a rod, emphasizing the adiabatic nature of the process due to insulation. The first law of thermodynamics is applied, indicating that internal energy change (U) equals the negative work done (W) since there is no heat transfer. The user expresses uncertainty about calculating work due to variable pressure and unknown paths, noting that the net work is zero when neglecting friction. Additionally, the forces on the pistons must balance, leading to a relationship between pressures and areas of the pistons. The conversation highlights the complexities of determining final state variables and the interdependence of work done in each cylinder.
flyers
Messages
28
Reaction score
0

Homework Statement


309mpv7.jpg



Homework Equations



First Law, U = Q-W
We also need to apply a force equillibrium on the pistons

The Attempt at a Solution


Since the problem says the walls and pistons are insulated, we know there is no heat transfer and the process is adiabatic but not reversible because of friction. So U = -W. I don't know the path and so I don't know how I could determine the work done but if I consider the system which contains both gases, the pistons and the rod (and the case where atm pressure = 0) then the work done is just 0 so U = 0. Therefore naCv(T2-T1)+nbCv(T2-T1) = 0. I also know that for final pressures, the forces acting on the rod must balance so pressure A*piston area of A = pressure B*piston area of B.

Beyond this I'm not so sure what to do since I don't know much on the final state variables. What confuses me most is how it would be possible to calculate work since the pressure is not constant and the path is unknown.
 
Physics news on Phys.org
The net work is indeed zero (neglecting the forces of friction). However, the work of gas in one cylinder must be equal to the work on gas in the other cylinder. You could also note that the changes of volumes in both cylinders are related quite simply.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top