Thermodynamics: Carnot Engine, WHY IS Qhot NEGATIVE?

EN!In summary, the conversation discusses the efficiency and energy input of a heat engine operating between 200°C and 80.0°C. The maximum possible efficiency is achieved at 20.0%, and the question is how much energy input is needed for the engine to perform 10.0 kJ of work. The equations used are e=1-Tc/Th and W=e*Qh, where Qh is typically denoted as negative and W can be either positive or negative depending on the convention. Qc is negative in this case as it represents heat leaving the system.
  • #1
Minari
1
0

Homework Statement


1. A heat engine operating between 200°C and 80.0°C achieves 20.0% of the maximum possible efficiency. What energy input will enable the engine to perform 10.0 kJ of work?


Homework Equations



e =1- Tc/Th
W=e*Qh

The Attempt at a Solution


I got the answer but I don't understand why Qh is negative and could you also explain why work is negative too? I'm guessing since the work is the output its negative? But why would the Qh be negative to isn't it the input? Also could you tell/explain when W, Qh and Qc are positive and negative? Thank you.
 
Physics news on Phys.org
  • #2
From U=Q+W

U + -> Internal energy gained by system
U - -> Internal energy lost by system

Q + -> Heat entering the system
Q - -> Heat leaving the system

W + -> Work done on the system
W - -> Work done by the systemR.
 
  • #3
Minari said:

Homework Statement


1. A heat engine operating between 200°C and 80.0°C achieves 20.0% of the maximum possible efficiency. What energy input will enable the engine to perform 10.0 kJ of work?


Homework Equations



e =1- Tc/Th
W=e*Qh

The Attempt at a Solution


I got the answer but I don't understand why Qh is negative and could you also explain why work is negative too? I'm guessing since the work is the output its negative? But why would the Qh be negative to isn't it the input? Also could you tell/explain when W, Qh and Qc are positive and negative? Thank you.
As Rick88 points out, it is the convention to denote heat leaving (eg. a reservoir) as negative and heat entering as positive. Whether Qh is negative or positive depends on your reference point. To the gas in the heat engine,
Qh is positive and Qc is negative. The convention for Work is less universal. The first law is now commonly written (in differential form):

dQ = dU + dW

where dW is the work done BY the system. In this form, work done BY the system is POSITIVE and work done ON the system is NEGATIVE. But it is just a convention. Not long ago, most textbooks used the opposite convention for W.

AM
 

1. What is a Carnot Engine?

A Carnot Engine is a theoretical heat engine that operates on the principles of the Carnot cycle. It consists of two isothermal and two adiabatic processes, and is used to understand the maximum efficiency that can be achieved by a heat engine.

2. How does a Carnot Engine work?

A Carnot Engine works by taking in heat from a hot reservoir at a constant temperature, performing work on a system, and then rejecting the remaining heat to a cold reservoir at a lower constant temperature. This process is repeated in a cycle, with the heat being converted to work and the engine's efficiency being determined by the temperature difference between the hot and cold reservoirs.

3. Why is Qhot negative in a Carnot Engine?

In a Carnot Engine, Qhot is negative because heat is being transferred out of the system to the cold reservoir. This is necessary for the engine to do work, as the second law of thermodynamics states that heat will naturally flow from a higher temperature to a lower temperature.

4. What is the significance of the Carnot cycle?

The Carnot cycle is significant because it represents the maximum possible efficiency that any heat engine can achieve. It serves as a theoretical benchmark for real heat engines, and helps to understand the limitations and potential improvements of these systems.

5. How does the efficiency of a Carnot Engine compare to other heat engines?

The efficiency of a Carnot Engine is higher than any other heat engine operating between the same two temperatures. This is because it operates on a reversible cycle, meaning that all processes are carried out without any energy loss. However, in practical applications, it is impossible to achieve the ideal efficiency of a Carnot Engine due to various factors such as friction and heat loss.

Similar threads

  • Introductory Physics Homework Help
Replies
2
Views
914
  • Advanced Physics Homework Help
Replies
8
Views
3K
  • Thermodynamics
Replies
3
Views
4K
  • Advanced Physics Homework Help
Replies
2
Views
2K
  • Introductory Physics Homework Help
Replies
20
Views
2K
  • Advanced Physics Homework Help
Replies
2
Views
3K
Replies
1
Views
511
  • Introductory Physics Homework Help
Replies
3
Views
3K
  • Introductory Physics Homework Help
Replies
2
Views
2K
  • Materials and Chemical Engineering
Replies
1
Views
2K
Back
Top