Thermodynamics - Cycle efficiency

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SUMMARY

The discussion centers on proving the efficiency η of a reversible thermodynamic cycle, defined as η = 1 - 2*T6 / (T1 + T3). Participants analyze the relationship between entropy values S1, S2, S4, and the temperatures T1, T3, and T6. Key insights include the correct interpretation of the areas in a T-S diagram, which represent heat exchanges, and the clarification of the relationship between entropies S2, S1, and S4. The conversation concludes with a participant resolving their confusion regarding the entropy relationships.

PREREQUISITES
  • Understanding of thermodynamic cycles and efficiency
  • Familiarity with T-S (Temperature-Entropy) diagrams
  • Knowledge of entropy and its role in thermodynamics
  • Basic equations of thermodynamics, particularly relating to heat transfer
NEXT STEPS
  • Study the derivation of efficiency formulas in thermodynamic cycles
  • Learn about the implications of entropy in reversible processes
  • Explore advanced concepts in thermodynamic diagrams and their applications
  • Investigate the impact of temperature variations on cycle efficiency
USEFUL FOR

Students of thermodynamics, engineers involved in energy systems, and anyone seeking to deepen their understanding of cycle efficiency in thermodynamic processes.

Jalo
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Homework Statement


Consider the following reversible cycle:

2ceqedh.png


Where S2=S3=(S1+S4)/2 .
Prove that the efficiency η is:

η= 1 - 2*T6 / (T1+T3)


Homework Equations





The Attempt at a Solution



I know that in a T-S diagram the heat received by the system is equal to the area delimited by the upper boundaries of the diagram and the line T=0. I also know that the heat dispensed by the system is equal to the area under the diagram (I got the same results calculating both heats analitically). Therefore I get:

η = 1 - (S4-S1)T6 / [ (S2-S1)T1+(S4-S2)T3 ] =
= 1 - 2*S2T6 / [ (S2-S1)T1+(S4-S2)T3 ]

I don't know how to get rid of the entropies tho... If anyone could point me in the right direction I'd appreciate.

Thanks!
 
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Jalo said:
η = 1 - (S4-S1)T6 / [ (S2-S1)T1+(S4-S2)T3 ] =
= 1 - 2*S2T6 / [ (S2-S1)T1+(S4-S2)T3 ]

Check the blue highlighted region. I don't believe it's correct. Note that S4-S1 ≠ 2S2

Also, think about the relation between S2-S1 and S4-S2
 
TSny said:
Check the blue highlighted region. I don't believe it's correct. Note that S4-S1 ≠ 2S2

Also, think about the relation between S2-S1 and S4-S2

Oh, for some reason I tought S2 was equal to (S4-S1)/2 instead of (S1+S4)/2 ...

I can solve it from here.
Thanks!
 

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