Thermodynamics - isochoric situation

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In an isochoric situation, the volume remains constant, leading to the equation βdT = KdP. To find the change in pressure (dP), the correct approach is to integrate this equation. The final pressure can be calculated using the formula ΔP = (β/K)(Tf - Ti), where Tf and Ti are the final and initial temperatures, respectively. The user initially struggled with their integration, mistakenly concluding that the final pressure equaled the initial pressure. Proper application of the integral will yield the correct final pressure.
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I'm trying to calculate the final pressure. I was given initial and final temperatures as well as initial pressure, expansitivy and isothermal bulk modulus. I was also told the volume is constant.

Since volume is constant I figured dV=0

so in the formula dV=VβdT - VKdP it reduces to:

βdT=KdP

I know that I need to solve for dP but I think I'm doing something wrong in my integral because I end up with the final pressure being the same as the initial pressure which I know is wrong. How do I solve that equation for dP?
 
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Your equation is correct. Just integrate. $$\Delta P=\frac{\beta}{K}(T_f-T_i)$$
 

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