Thermodynamics of Multicomponent Systems

AI Thread Summary
The discussion centers on solving a calorimetric problem involving triethylamine-benzene solutions at 298.15 K. Participants are asked to develop expressions for the partial molar enthalpies of benzene and triethylamine and compute their values at a specific concentration. Additionally, the heat required for mixing two benzene mixtures at different concentrations is to be determined to maintain isothermal conditions. The thread emphasizes the need for a structured approach and encourages posting in the appropriate forum for homework help. Overall, it highlights the importance of showing work in problem-solving for clarity and understanding.
Mir17
Messages
2
Reaction score
0
Can someone provide me with a general understanding of the steps involved in completing this problem. How do I get started?

Calorimetric data on triethylamine (EA)-benzene (B) solutions at 298.15 K were obtained and follow the following expression: Hmix – [xBHB + (1 - xB)HEA] = xB(1 - xB)[1418 - 482.4(1 - 2xB) + 187.4(1 – 2xB)3]

(a)Develop expressions for (HB - HB) and (HEA - HEA). Note that Hi is the partial molar enthalpy of a species.

(b)Compute values for (HB - HB) and (HEA - HEA) at xB = 0.5. (c) One mole of a 25 mol% benzene mixture is to be mixed with one mole of a 75 mol% benzene mixture at 298.15 K. How much heat must be added or removed from the process to be isothermal?
 
Engineering news on Phys.org
Mir17 said:
Can someone provide me with a general understanding of the steps involved in completing this problem. How do I get started?

Calorimetric data on triethylamine (EA)-benzene (B) solutions at 298.15 K were obtained and follow the following expression: Hmix – [xBHB + (1 - xB)HEA] = xB(1 - xB)[1418 - 482.4(1 - 2xB) + 187.4(1 – 2xB)3]

(a)Develop expressions for (HB - HB) and (HEA - HEA). Note that Hi is the partial molar enthalpy of a species.

(b)Compute values for (HB - HB) and (HEA - HEA) at xB = 0.5. (c) One mole of a 25 mol% benzene mixture is to be mixed with one mole of a 75 mol% benzene mixture at 298.15 K. How much heat must be added or removed from the process to be isothermal?

Check your PMs. This needs to be posted in the Homework Help, Chemistry forum, and you need to show your work toward a solution. This thread is locked.
 
Back
Top