Can someone provide me with a general understanding of the steps involved in completing this problem. How do I get started? Calorimetric data on triethylamine (EA)-benzene (B) solutions at 298.15 K were obtained and follow the following expression: Hmix – [xBHB + (1 - xB)HEA] = xB(1 - xB)[1418 - 482.4(1 - 2xB) + 187.4(1 – 2xB)3] (a)Develop expressions for (HB - HB) and (HEA - HEA). Note that Hi is the partial molar enthalpy of a species. (b)Compute values for (HB - HB) and (HEA - HEA) at xB = 0.5. (c) One mole of a 25 mol% benzene mixture is to be mixed with one mole of a 75 mol% benzene mixture at 298.15 K. How much heat must be added or removed from the process to be isothermal?