Thermodynamics: polytropic processes

AI Thread Summary
The discussion focuses on calculating the work done during a polytropic process where the relationship PV^n = c is applied. The user initially attempted to solve the problem by integrating with a constant pressure of 150 kPa, resulting in an incorrect work value. The correct approach involves determining the final pressure using the relationship provided and then applying the work formula for polytropic processes. The final solution yields a work done of 6.51 kJ after correctly calculating the constant C from the initial state. The user successfully resolves the misunderstanding with guidance from the forum.
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Homework Statement


"During some actual expansion and compression processes in piston-cylinder devices, the gases have been observed to satisfy the relationship PV^n=c where n and C are constants. Calculate the work done when a gas expands from 150kPa and .03 m^3 to a final volume of .2m^3 for the case of n = 1.3


Homework Equations


W = \int_{1}^{2} {P}dV


The Attempt at a Solution


PV^n=C \Rightarrow P=CV^{-n} \Rightarrow<br /> W = \int_{.03}^{.2} {150V^{-1.3}}dV = 621 kJ
Which...is wrong :(

The solution the book offers is:
P_{2} = P_{1}\frac{V_{1}}{V_{2}}^n = (150)\frac{.03}{.2}^{1.3} = 12.74 kPa<br /> \Rightarrow W = \int_{1}^{2} {P}dv = \frac{P_{2}V_{2} - P_{1}V_{1}}{1-n}<br /> =\frac{(12.74 \cdot .2 - 150 \cdot .03)}{1-1.3} = 6.51 kJ

Could someone explain why the way i did it is "unacceptable"?
 
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Because C\neq150; check your integrand.
 
Oh...woops
I put in 150 because i was still thinking that W = P\Delta V and I put in 150
then what would i put in? the question does not supply C though
 
You can calculate C from initial state.

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methods
 
oh lol!
ok, i got the answer, thanks :)
 
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