Thermodynamics Problem: Heat and Vapor Formation in a Piston-Cylinder Device

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The discussion focuses on a thermodynamics problem involving a piston-cylinder device containing 10 kg of water at 85°C. The calculations for the heat required to initiate vapor formation yielded 614.4 kJ, while raising the piston 0.2 meters required 4.8 kJ, confirmed through various methods including specific volume calculations and work done assessments. A T-v diagram was drawn to illustrate the process, with the final temperature calculated to be 133.52°C, indicating saturation conditions. A participant raised a concern about the atmospheric pressure used in the calculations, suggesting that the standard value of 101.345 kPa might significantly affect the results. Overall, the calculations and methodology were affirmed, but the pressure discrepancy was noted for further consideration.
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A piston-cylinder device initially contains 10 kg. of water at a temperature of 85 C. The cylinder has a section area of 0.12 meter square and the piston has no mass. A linear spring (spring constant 120,000 N/m) is touching the piston as shown but exerts no force on it initially. Then heat is slowly added to the water in the cylinder, determine: (assume atmospheric pressure to be 100 kPa)

a) How much heat is needed to start to form vapor in the cylinder?

b) How much heat is needed to raise the piston 0.2 meter above its original position.

c) Show the process on a T-v diagram with respects to saturation lines.


For answer a I got 614.4 KJ from m ( u2-u1) the change in the internal energies multiplied by the mass using u2 at 100 kPa at the sat temp. and u1 from Tsat @ 85 C since it can be reasonably substituted for a compressed liquid.

For answer b I got 4.8 KJ

V1= 10kg* .001032 (Vf@85 C)
V2= .01032+.12*.2

One way i did it was find the specific volumes then finding the total volumes and drawing a P-V Diagram and looking at the area under the curve, then checking it by calculating the total work done.

300+100 * 1/2 * (.03432-.01032) =4.8kj

checking using work methods ( 1/2kx^2 + pressure*area*distance)
1/2 * 120 * .2^2 + 100*.2*.12=4.8kj

C) did a check of specific volumes to confirm that the final temp was indeed the saturation temperature. then drew the T-V diagram. 133.52 C is my final temp that i calculated.

vf@300kpa vg@300kpa
.001073<.0034232<.60582 --> is the saturated temperature


Could someone please confirm these results? :)

THANK YOU!
 
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yes you r right(to all i know)(to very sure but in he rite trak)...but 1atm is 101.345kpa...doesnt dat cause a significant variation in you ans?
 
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